Whatb is differentiation of e^ax^2+b...?

1 Answer
Feb 4, 2018

Please see below.

Explanation:

Answer 1

As presented, the question asks for the derivative (presumably with respect to #x#) of

#y = e^ax^2+b#.

Assuming that #a# and #b# are constants, #e^a# is a constant, so we can simply use the power rule to get

# dy/dx = 2e^ax#

Answer 2

It seems likely that the intended question asks for the derivative (presumably with respect to #x#) of

#y = e^(ax^2+b)#.

For this we need the chain rule for #e# to a power which can be written

#d/dx(e^u) = e^u * (du)/dx " "# or #" "d/dx(e^(g(x))) = e^(g(x)) * g'(x)#

We get

#dy/dx = e^(ax^2+b) * 2ax#.

We might prefer to write this: #dy/dx = 2axe^(ax^2+b)#