# When 435 J of heat is added to 3.4 g of olive oil at 21 C, the temperature increases to 85 C. What is the specific heat of the olive oil?

$Q = m {c}_{\text{sp}} \Delta T$; thus ${c}_{\text{sp}} = \frac{Q}{\Delta T \cdot m}$
${c}_{\text{sp}} = \frac{435 \cdot J}{64 \cdot K \cdot 3.4 \cdot g}$ $\cong$ $\frac{5}{2} \cdot J \cdot {K}^{-} 1 {g}^{-} 1$.