When 56.6 g of calcium is reacted with nitrogen gas, 32.4 g of calcium nitride is produced. What is the percent yield of calcium nitride in the reaction #3Ca(s) + N_2(g) -> Ca_3N_2(s)#?

1 Answer
anor277
Aug 15, 2016

#"% yield"# #<# #50%#

Explanation:

#3Ca(s) + N_2(g) rarr Ca_3N_2(s)#

#"Moles of calcium metal"# #=# #(56.6*g)/(40.08*g*mol^-1)# #=# #1.41*mol#.

#"Moles of calcium nitride"# #=# #(32.4*g)/(148.25*g*mol^-1)# #=# #0.219*mol#.

Given the equation, #0.470*mol# calcium nitride would be obtained if the yield were quantitative.

#"Yield"# #=# #(0.219*mol)/(0.470*mol)xx100%# #=# #??#

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