When a car moves uniformly from 42 km/h to68km/h in 30s. find distance travelled by the car?

1 Answer
Feb 23, 2018

The car traveled a distance of #216.66m~=2xx10^2m#.

Explanation:

#[(68km)/h]xx[(1000m)/(km)]xx[(1h)/(3600s)]~=18.889m/s#

#[(42km)/h]xx[(1000m)/(km)]xx[(1h)/(3600s)]~=11.667m/s#

Since the velocity increases at a constant rate, that is the acceleration is constant, we can use this simple velocity formula.

#Deltav=(Deltad)/(Deltat)#
where v is velocity, d is distance, and t is time. The delta symbol,

#Delta#, simply means the change or difference in values.

Rearrange this velocity formula to find distance, d.

#Deltad=(Deltav)xx(Deltat)#

Now substitute the values in for their respective variables.

#Deltad~=(18.889m/s-11.667m/s)xx30s~=(7.222)xx30s~=216.66m~=2xx10^2m#