When considering the system (−1x+2y= -13) and (2x−4y=26) What are the solution to the system? If there are infinitely many solutions let y=t and solve for x in terms of t ?

1 Answer
Sep 6, 2015

There are infinitely many solutions of the chosen form #x=2t+13# and #y=t#

Explanation:

If we try to solve

#−1x+2y= -13# and #2x−4y=26#

We get a tautology like #13=13# or #0=0# true for all values of the variables.
This implies that every solution of one equation is a solution of the other.

To writ the solutions using #y=t#, substitute for #y# in either equation and solve for #x#.

You will get #x=2t+13#

One way to write the solution set is:

#{(2t+13,t)| t in RR}#