# When iron rusts in air, iron (Ill) oxide is produced. How many moles of oxygen react with 6.4 mol of iron in the rusting reaction?

Jun 16, 2018

$\text{4.8 mol O"_2}$ react with $\text{6.4 mol Fe}$.

#### Explanation:

Balanced equation

$\text{4Fe(s) + 3O"_2("g")}$$\rightarrow$$\text{2Fe"_2"O"_3("s")}$

Multiply the given moles of iron by the mole ratio between oxygen and iron from the balanced equation, with moles oxygen in the numerator.

6.4color(red)cancel(color(black)("mol Fe"))xx(3"mol O"_2)/(4color(red)cancel(color(black)("mol Fe")))="4.8 mol O"_2"