# When lead(l) nitrate reacts with sodium iodide, what is the formula for the product lead (lI) iodide?

Nov 14, 2016

$\text{Lead(II) iodide}$ $\equiv$ $P b {I}_{2}$

#### Explanation:

$P {b}^{2 +} + 2 {I}^{-} \rightarrow P b {I}_{2} \left(s\right) \downarrow$

$\text{Lead(II) iodide}$ or (more rarely) $\text{plumbous iodide}$ is a water insoluble, fine yellow powder.

In the given reaction, both mass and charge have been conserved. What does this mean?

The reaction of halides with lead nitrate is often a useful way to identify an unknown halide. $P b C {l}_{2}$ forms an insoluble white precipitate; $P b B {r}_{2}$ forms an insoluble cream-coloured precipitate; and $P b {I}_{2}$ forms an insoluble bright yellow precipitate.