When lead(l) nitrate reacts with sodium iodide, what is the formula for the product lead (lI) iodide?

1 Answer
Nov 14, 2016

Answer:

#"Lead(II) iodide"# #-=# #PbI_2#

Explanation:

#Pb^(2+) + 2I^(-) rarr PbI_2(s)darr#

#"Lead(II) iodide"# or (more rarely) #"plumbous iodide"# is a water insoluble, fine yellow powder.

In the given reaction, both mass and charge have been conserved. What does this mean?

The reaction of halides with lead nitrate is often a useful way to identify an unknown halide. #PbCl_2# forms an insoluble white precipitate; #PbBr_2# forms an insoluble cream-coloured precipitate; and #PbI_2# forms an insoluble bright yellow precipitate.