When $(n + 3) (n + 2)!$ $(n + 3) (n +2)!$ is multiplied by $(n + 4)$ $(n +4)$ and then divided by $(n + 2)!,$ $(n+ 2)!,$ what is the result?

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Answer 1 · 2017-03-29T17:43:12

$(n + 3) (n + 4)$ $(n+3)(n+4)$

$\frac{(n + 3) (n + 2)! \cdot (n + 4)}{(n + 2)!} = (n + 3) (n + 4)$ $((n+3)(n+2)!*(n+4))/((n+2)!)=(n+3)(n+4)$

When (n+3)(n+2)!(n + 3) (n +2)! is multiplied by (n+4) (n +4) and then divided by (n+2)!,(n+ 2)!, what is the result?