# When rolling a fair, six-sided die, what is the probability of getting a number higher than 2?

Mar 20, 2017

$\frac{2}{3}$

#### Explanation:

we want $P \left(X > 2\right)$

for a fair die the sample space is$\text{ } \left\{1 , 2 , 3 , 4 , 5 , 6\right\}$

all the numbers are equiprobable

there are $\text{ "4" }$ numbers greater than 2 so we have

$P \left(X > 2\right) = \frac{4}{6} = \frac{2}{3}$