Question

When `x=3` and `y=5`, by how much does the value of `3x^2-2y` exceed the value of `2x^2-3y`?

Answer 1

14

Explanation:

We have `f(x,y) = 3x^2 -2y` and `g(x,y) = 2x^2 - 3y`.

Define a new function `d(x,y) = f(x,y) - g(x,y)`

`d(x,y) = 3x^2 - 2y - (2x^2 - 3y)`

`d(x,y) = x^2 + y`

`d(3,5) = (3)^2 + 5 = 9 + 5 = 14`