Where does the graph of #y=-0.5x-2# cross the x-axis?

1 Answer
Aug 28, 2017

See a solution process below:

Explanation:

To graph this equation first, solve for two points which solve the equation and plot these points:

First Point:

For #x = 0#

#y = 0 - 2#

#y = -2# or #(0, -2)#

Second Point:

For #x = 2#

#y = -1 - 2#

#y = -3# or #(2, -3)#

We can next graph the two points on the coordinate plane:

graph{(x^2+(y+2)^2-0.0125)((x-2)^2+(y+3)^2-0.0125)=0 [-6, 6, -4, 2]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y+0.5x + 2)(x^2+(y+2)^2-0.0125)((x-2)^2+(y+3)^2-0.0125)=0 [-6, 6, -4, 2]}

From the graph we can see the line crosses the #x#-axis at #-4# or #(-4, 0)#