Which two consecutive integers are such that the smaller added to the square of the larger is 21?

2 Answers
Oct 10, 2017

None!

Explanation:

Let the larger no. be x.
Then, the smaller no. will be x1.

According to the que,
x2+(x1)=21
=x2+x22=0

Use quadratic formula with a=1,b=1,c=22

x=b±b24ac2a

x=(1)±(1)24(1)(22)2(1)

x=1±892

So, there is no integer root for this equation.

Oct 10, 2017

5,4

Explanation:

Let n be the larger integer then: n - 1 is the smaller integer we have:

n+(n1)2=21
n+n22n+1=21
n2n20=0
(n+4)(n5)=0
n=4,n=5
n1=5,n1=4
reject the positive roots thus:
-5 and -4 are the integers