Which would contain 9.03 × 10^23 oxygen atoms? A) 0.25 mol aluminium oxide B) 0.75 mol sulfur dioxide C) 1.5 mol sulfur trioxide D) 3.0 mol water

2 Answers
Nov 25, 2017

Well one mole of stuff specifies 6.022xx10^23 individual items of stuff.....

Explanation:

But of course we must specify the item. In the first scenario we gots 0.25*mol "aluminium oxide", i.e. Al_2O_3..approx. 4.5xx10^23*"oxygen atoms"...

And in the second scenario we gots 6.022xx10^23*mol^-1xx2xx0.75*mol "oxygen atoms"=9.0xx10^23*"oxygen atoms". So it looks like scenario 2 is the winner. And scenario 3 and 4 contain too many oxygen atoms to fulfil your given criterion.

Nov 25, 2017

B

Explanation:

0.75 mol sulphur dioxide = 0.75 mol of sulphur +1.5 mol of oxide

1.5 mol = 1.5 * 6.02 * 10^23 = 9.03*10^23

1.5 mol of oxide = 0.75 mol dioxide = 9.03*10^23 oxygen atoms