# Why does (5 times the square root of 3) plus the square root of 27 equal 8 times the square root of 3?

$\sqrt{27} = \sqrt{{3}^{3}} = 3 \sqrt{3}$
$5 \sqrt{3} + \sqrt{27} = 5 \sqrt{3} + 3 \sqrt{3} = 8 \sqrt{3}$