Why is cos2x the answer of -sin^2x + cos^2x?

2 Answers
May 21, 2016

I tried this....hope it helps!

Explanation:

You know that #sin^2(x)+cos^2(x)=1#
so rearranging:
#sin^2(x)=1-cos^2(x)#

substituting into your expression you get:

#-1+cos^2(x)+cos^2(x)=2cos^2(x)-1#

Now let us choose an angle #x#, say #pi/3#:
we have:
#2cos^2(x)-1=2cos^2(pi/3)-1=2*(1/2)^2-1=-1/2#
or:
#cos(2x)=cos(2pi/3)=-1/2#
You can try with other angles to see it!!!

May 21, 2016

See below

Explanation:

Use the Property:#cos(A+B)= cosAcosB-sinAsinB#
Left Side:#cos 2x= cos(x+x)=cosx cosx -sinx sinx#

#=cos^2x-sin^2x#

#=#Right Side