Why parametric equations of the parabola #y^2 = 4ax# is #y =2at# and #x = at^2# . why can't #y =4at# and #x = 4at^2#. Because #y = 4at# and #x = 4at^2# also satisfies the equation #y^2 = 4ax# right ?

1 Answer
Jan 11, 2018

Parametric equations are not unique.

Explanation:

Start with #y^2 = 4ax#

y is the domain and it is #-oo < y < oo#

x is the range and it is #0 <=x < oo#

Let's check your parametric equations #y = 4at# and #x = 4at^2#.

#(4at)^2 = 4a(4at^2)#

#16a^2t^2 = 16a^2t^2# It seems to satisfy the equation

y has the domain #-oo < y < oo#
x has the range #0 <= x < oo#

Let #a=2# and look at the two graphs for #color(red)(y^2 = 8x)# and #color(blue)((8t^2,8t); -oo < t < oo)#

www.desmos.com/calculator

www.desmos.com/calculator

The two graphs are identical.

I am sure that you can find other parametric equations for the same graph. For example, #y = t# and #x = t^2/(4a)#