Will these reactions yield an acidic, basic or neutral solution?

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1 Answer
May 9, 2017

Answer:

We assume one equiv EACH of the given reagents.........

Explanation:

And thus for #a.,b.,c.# we gets acidic, slightly basic, and basic solutions.

And we should write the stoichiometric equations:

#a.# #H_2SO_4(aq) +NH_3(aq) rarr NH_4^+ + HSO_4^-#

The solution is ACIDIC because of the acidity of both bisulfate and ammonium ions:

#HSO_4^(-) +H_2O rightleftharpoons H_3O^+ + SO_4^(2-)#

#b.# #HCO_2H(aq) +KOH(aq) rarr HCO_2^(-)K^+ + H_2O(l)#

and potassium formate gives a slightly basic solution.......

#K^+HCO_2^(-) +H_2O rightleftharpoons HCO_2H(aq) + KOH(aq)#

The solution is ALKALINE because of the basicity of the formate ions.

#(c)# #CaCO_3(s) + HNO_3(aq) rightleftharpoons [CaHCO_3]^ + +NO_3^(-) +H_2O#

The solution should be more or less neutral.