# Will these reactions yield an acidic, basic or neutral solution?

## May 9, 2017

We assume one equiv EACH of the given reagents.........

#### Explanation:

And thus for $a . , b . , c .$ we gets acidic, slightly basic, and basic solutions.

And we should write the stoichiometric equations:

$a .$ ${H}_{2} S {O}_{4} \left(a q\right) + N {H}_{3} \left(a q\right) \rightarrow N {H}_{4}^{+} + H S {O}_{4}^{-}$

The solution is ACIDIC because of the acidity of both bisulfate and ammonium ions:

$H S {O}_{4}^{-} + {H}_{2} O r i g h t \le f t h a r p \infty n s {H}_{3} {O}^{+} + S {O}_{4}^{2 -}$

$b .$ $H C {O}_{2} H \left(a q\right) + K O H \left(a q\right) \rightarrow H C {O}_{2}^{-} {K}^{+} + {H}_{2} O \left(l\right)$

and potassium formate gives a slightly basic solution.......

${K}^{+} H C {O}_{2}^{-} + {H}_{2} O r i g h t \le f t h a r p \infty n s H C {O}_{2} H \left(a q\right) + K O H \left(a q\right)$

The solution is ALKALINE because of the basicity of the formate ions.

$\left(c\right)$ $C a C {O}_{3} \left(s\right) + H N {O}_{3} \left(a q\right) r i g h t \le f t h a r p \infty n s {\left[C a H C {O}_{3}\right]}^{+} + N {O}_{3}^{-} + {H}_{2} O$

The solution should be more or less neutral.