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Question

tan(35°)cot(55°) - sec(55°)csc(55°)

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Answer 1 · 2018-04-16T10:00:21

#tan 35 * cot 55 - sec 35 * csc 55 = 1#

#tan 35 * cot 55 - sec 35 * csc 55#

#cot theta = tan (90 - theta), csc theta = sec (90 - theta)#

#:. tan 35 * tan (90-55) - sec 35 * sec (90-55)#

#tan 35 * tan 35 - sec 35 * sec 35#

#=>tan^2 35 - sec ^2 35#

#:. => -1, " as we know, " sec^2 theta - tan^2 theta = 1#