Simplify the following? #(x^(5/4) sqrt(16x^3)) /(8x)^(2/3)#

1 Answer

#x^(25/12)#

Explanation:

I think the question here is to simplify the following:

#(x^(5/4)sqrt(16x^3))/(8x)^(2/3)#

I'll first move the term out of the denominator. Remember that #1/x=x^(-1)#, so we can rewrite the denominator:

#1/(8x)^(2/3)=(8x)^(-2/3)#

and we can simplify further:

#(8x)^(-2/3)=8^(-2/3)x^(-2/3)=(2^3)^(-2/3)x^(-2/3)=2^(3xx(-2/3))x^(-2/3)=2^-2x^(-2/3)#

We can now write the original as:

#(x^(5/4)sqrt(16x^3))/(8x)^(2/3)=(x^(5/4))(sqrt(16x^3))(2^-2x^(-2/3))#

Let's rewrite the middle term:

#sqrt(16x^3)=16^(1/2)x^(3/2)=4x^(3/2)#

And substitue in:

#(x^(5/4))(4x^(3/2))(2^-2x^(-2/3))#

Let's now do the multiplication. I'll group the constants together and the variables together:

#(4)(2^-2)xx(x^(5/4))(x^(3/2))(x^(-2/3))#

For the constants, we have:

#4xx2^-2=4xx1/4=1#

For the variables, remember that we can use the rule

#x^a xx x^b = x^(a+b)#

We have:

#(x^(5/4))(x^(3/2))(x^(-2/3))=x^(5/4+3/2-2/3)=x^(15/12+18/12-8/12)=x^(25/12)#