Question

How do you solve `x=b-cd,` for `c?`

Answer 1

`c = (b-x)/d`

Explanation:

This means that you want to make `c` the subject, ie so `color(blue)(c)` is alone on one side.

`x = b-color(blue)(c)d" "larr` make the term with `color(blue)(c)` positive.

Add `cd` to both sides:

`color(blue)(c)d+x = b-color(blue)(c)d+color(blue)(c)d`

`color(blue)(c)d+x-x = b -x" "larr` subtract `x` from both sides

`color(blue)(c)d = b-x`

Divide both sides by `d` to isolate `color(blue)(c)`

`(color(blue)(c)d)/d = (b-x)/d`

`color(blue)(c) = (b-x)/d`