Question

You have a coin which is loaded so that the probability of tossing heads is .55. If you toss the coin three times, what is the probability that you will obtain three heads?

Answer 1

`P_(3h,"loaded") = p_h*p_h*p_h=p_h^3 = 0.55^3 ~= 0.166`

Explanation:

Since there is only one way to throw three heads, we only need to assess the probability of this one situation, which is throwing heads in each of three subsequent throws, i.e.

`P_(3h,"loaded") = p_h*p_h*p_h=p_h^3 = 0.55^3 ~= 0.166`

For reference, the probability of a "normal" coin, this probability would be

`P_(3h,"normal") = p_h*p_h*p_h=p_h^3 = 0.5^3 ~= 0.125`