Question

You mix about 375 grams of sugar (C12H22O11) with 1255 mL of water (remember: density of water = 1.00 g/mL). What is the molality of the solution?

Answer 1

Well `"molality"="moles of solute"/"kilograms of solute"`

Explanation:

And thus....`((375*g)/(342.31*g*mol^-1))/(1.255*kg)=0.873*mol*kg^-1`..

Note the molarity of the solution would not be so much different...certainly molarity would be equal to a first approx....