# You need to measure out .23 mol of C8H16O8 for an experiment. How many grams would you need to weigh out?

Apr 26, 2018

#### Answer:

55.2497g ${C}_{8}$${H}_{16}$${O}_{8}$

#### Explanation:

$.23 m o l$ ${C}_{8}$${H}_{16}$${O}_{8}$

First, let's find the molar mass of ${C}_{8}$${H}_{16}$${O}_{8}$ by calculating the mass of each element.

Carbon weighs 12.011 grams, and we have 8 of those. Multiply.

$96.088$g Carbon

Hydrogen weighs 1.008 grams, and we have 16 of those. Multiply.

$16.128$g Hydrogen

Oxygen weighs 15.999, or 16g, and we have 8 of those. Multiply.

$128$g Oxygen

Add the atomic masses.

$240.216$g is the molar mass of ${C}_{8}$${H}_{16}$${O}_{8}$.

Now, to find the number of grams needed, set up a proportion.

$.23 m o l$ ${C}_{8}$${H}_{16}$${O}_{8}$ $\cdot$ $\left(\frac{240.216}{1}\right)$, where 240.216 represents the molar mass of the substance and 1 represents the # of moles. Divide accordingly. Moles on top and bottom cancel out.

Answer: 55.2497g ${C}_{8}$${H}_{16}$${O}_{8}$