You roll a number cube twice. What is the probability of rolling an even number and a 5?

2 Answers
May 4, 2018

#1/6#

Explanation:

P(even)=#1/2#

P(5)=#1/6#

So the probability of #(even nn 5)=1/2xx1/6=1/12#
But you could also get #(5 nn even)1/12#

#1/12+1/12=1/6#

May 4, 2018

#6/36 = 1/6#

Explanation:

Before we calculate an answer, drawing a possibility space allows us to see all the #36# outcomes of throwing a cube twice.
The grid shows the sum of the two throws.

The red values are those which have a #5# and and an even number

#6|" "7" "8" "9" "10" "color(red)(11)" "12#
#5|" "6" "color(red)(7)" "8" "color(red)(9)" "10" "color(red)(11)#
#4|" "5" "6" "7" "8" "color(red)(9)" "10#
#3|" "4" "5" "6" "7" "8" "9#
#2|" "3" "4" "5" "6" "color(red)(7)" "8#
#1|ul(" "2" "3" "4" "5" "6" "7)#
#color(white)(xxxx)1" "2" "3" "4" "5" "6#

#P(5 and "even") = 6/36 =1/6#

Using a calculation:

#P(5 and "even") = P(5, "even") " OR " P("even", 5)#

#= (1/6 xx 3/6) + (3/6 xx1/6)#

#=3/36 +3/36#

#=6/36#

#=1/6#