# You roll a standard number cube. How do you find P(number greater than 3)?

$P \left(\text{number} > 3\right) = \frac{3}{6} = \frac{1}{2}$
There are 6 numbers on a standard number cube, $1 - 6$. The numbers greater than 3 are 4, 5, 6. Therefore there are 3 ways to satisfy the requirement that the number rolled be greater than 3 out of 6 total numbers possible:
$P \left(\text{number} > 3\right) = \frac{3}{6} = \frac{1}{2}$