SOCRATIC
Subjects
Science
Anatomy & Physiology
Astronomy
Astrophysics
Biology
Chemistry
Earth Science
Environmental Science
Organic Chemistry
Physics
Math
Algebra
Calculus
Geometry
Prealgebra
Precalculus
Statistics
Trigonometry
Humanities
English Grammar
U.S. History
World History
... and beyond
Socratic Meta
Ask question
Log in
Sign up
×
Loading...
Barry H. has helped students
times in
Activity
Summary of contribution activity by day
On a 1 day streak. Longest streak: 6 days
5 thank you notes
@amelia-3
Anon
Thank you so much this really helped :)
for this
answer
3 weeks ago
·
Like
@jeish-g
Jeish G.
Thank you so much!
for this
answer
1 month ago
·
Like
@rafid-k
Rafid K.
Thanks yo so much!
for this
answer
2 months ago
·
Like
Show more
Barry H.
Barry H. joined Socratic 5 months ago. Barry H. hasn't written a biography yet.
6,800 karma
Recent collaborators
Activity
77 Answers
13 Edits
@barry-h-1
Barry H.
wrote an answer to
Calculate Y' and Y'' at the point (2,6)?
.
yesterday
·
Like
@barry-h-1
Barry H.
commented
Yes, thank you again. I am still quite unfamiliar with how to navigate about the site in respect of syntax and how to alter ' things'. Will persevere, and am most grateful for any advice from a professional mathematician.
on
Pressure (p) and volume (v) given in eqn #pv^1.4=k# where k is constant. At certain instant pressure is #(25gm)/(cm^3# and volume is #32cm^3#. If volume is increasing at rate of #(5cm^3)/s#, how do you find the rate at which pressure is changing?
1 week ago
·
Like
@barry-h-1
Barry H.
updated
the answer to
Pressure (p) and volume (v) given in eqn #pv^1.4=k# where k is constant. At certain instant pressure is #(25gm)/(cm^3# and volume is #32cm^3#. If volume is increasing at rate of #(5cm^3)/s#, how do you find the rate at which pressure is changing?
.
1 week ago
·
Like
@barry-h-1
Barry H.
commented
Thank you for pointing out my error Which I have now corrected and believe to be correct.
on
Pressure (p) and volume (v) given in eqn #pv^1.4=k# where k is constant. At certain instant pressure is #(25gm)/(cm^3# and volume is #32cm^3#. If volume is increasing at rate of #(5cm^3)/s#, how do you find the rate at which pressure is changing?
1 week ago
·
Like
Ultrilliam liked this.
@barry-h-1
Barry H.
commented
Thank you for checking this answer which I have now corrected and I believe to be correct.
on
Pressure (p) and volume (v) given in eqn #pv^1.4=k# where k is constant. At certain instant pressure is #(25gm)/(cm^3# and volume is #32cm^3#. If volume is increasing at rate of #(5cm^3)/s#, how do you find the rate at which pressure is changing?
1 week ago
·
Like
@barry-h-1
Barry H.
updated
the answer to
Pressure (p) and volume (v) given in eqn #pv^1.4=k# where k is constant. At certain instant pressure is #(25gm)/(cm^3# and volume is #32cm^3#. If volume is increasing at rate of #(5cm^3)/s#, how do you find the rate at which pressure is changing?
.
1 week ago
·
Like
@barry-h-1
Barry H.
wrote an answer to
Pressure (p) and volume (v) given in eqn #pv^1.4=k# where k is constant. At certain instant pressure is #(25gm)/(cm^3# and volume is #32cm^3#. If volume is increasing at rate of #(5cm^3)/s#, how do you find the rate at which pressure is changing?
.
1 week ago
·
Like
@barry-h-1
Barry H.
commented
To clarify, should this question not say pressure =#25# gm cm^2 and not #25# gm cm^3, since pressure is defined as force/ area?
on
Pressure (p) and volume (v) given in eqn #pv^1.4=k# where k is constant. At certain instant pressure is #(25gm)/(cm^3# and volume is #32cm^3#. If volume is increasing at rate of #(5cm^3)/s#, how do you find the rate at which pressure is changing?
1 week ago
·
Like
@barry-h-1
Barry H.
wrote an answer to
How do you find the volume bounded by #y^2=x^3# and #y=x^2# revolved about the y-axis?
.
1 week ago
·
Like
@barry-h-1
Barry H.
wrote an answer to
A particle is moving along the curve whose equation is #8/5=(xy^3)/(1+y^2)#. Assume that the x-coordinate is increasing at the rate of 6 units/sec when the particle is at the point (1,2). At what rate is y-coordinate of the point changing at that instant?
.
1 week ago
·
Like
Show more activity
Loading...
Loading...
Loading...