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Let ABC be a triangle with AB=AC. The bisector of angle ACB meet AB at M. Suppose AM+MC=BC. Show that angle BAC = 100 degrees?
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Please help?!?
This question has landed me in a total disaster.
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Refer to the image?!

The two opposite vertices of a square are at (3,4) and (1,1). What will be the other two vertices of the square?

What is: ?

What is the final velocity(v)?
Given: u=0, mass of the object=10kg, BC=10m, ABC is rightangled, and angle CAB=30 degrees. Refer to the image:

What is the the value of a? Also, prove the following:

What is the value of #k# ?

What is the number of REAL solutions of the following equation?