Questions asked by patrick peter y.
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How do I prove that #x=1# or #0# from solving #3^(2x+1) - 12(3^x) + 9 = 0#?
Solve 3^(2x+1) - 28 (3^x-1) +1=0?
At what rate will the sum of 1200 amount to 2348.32 in 2yrs? if compounded quarterly
Simplify 2log(x+4)^2 - 2logx =1/4?
Simplify #(81/16)^(-3/9)#?