Question #7580c
1 Answer
The yield of Fe₂O₃ is 79.3 %.
This is a three-part question. "They" gave you the masses of two reactants, so the first problem is
1. Determine the limiting reactant. Then
2. Calculate the theoretical yield. Finally
3. Calculate the percentage yield.
Determine the limiting reactant.
Write the balanced equation.
4FeS₂ + 11O₂ → 2Fe₂O₃ + 8SO₂
Calculate the amount of Fe₂O₃ formed from each reactant.
From FeS₂: 300 g FeS₂ ×
From O₂: 200 g O₂ ×
Since O₂ gives the smallest amount of Fe₂O₃, O₂ is the limiting reactant.
Calculate the Theoretical Yield
Theoretical yield = 1.136 mol Fe₂O₃ ×
Calculate the Percentage Yield
Percentage Yield =
Hope this helps.