Question

A certain sample of gas has a volume of 0.452 L measured at 87°C and 0.620 atm. What is its volume at 1 atm and 0°C?

Answer 1

To solve this problem we would use the combined gas law.

The formula for the combined gas law is
`((P_i)(V_i))/T_i = ((P_f)(V_f))/T_f`

We begin by identifying the values for each of the variables and identifying the missing value.

`P_i` = 0.620 atm
`V_i` = 0.452 L
`T_i` = 87 C + 273 = 360 K

`P_f` = 1 atm
`V_f` = ???
`T_f` = 0 C + 273 = 273 K

`((0.620 atm)(0.452 L))/(360 K) = ((1 atm)(x))/(273 K)`

`((273 K)(0.620 atm)(0.452 L))/((360 K)(1atm)) = (x L)`

`x L = 0.212 L`

I hope this was helpful.
SMARTERTEACHER