What is the series equivalent of two 1000 W resistors in series?

1 Answer
Aug 24, 2014

I think you mean Omega and not W. The answer is 2000Omega.

Resistors in series are simply summed (added) up.

If you actually mean W, then we need a different calculation:

P=VI=VV/R=(V^2)/R
1000=(V^2)/R
This is for 1 resistor.

Recall that the voltage is split between the resistors, so total voltage is double, V_T=2V. So, summing up the wattage, we get:
2000=((V_T)^2)/(R_T)=((2V)^2)/(R_T)
2(V^2)/R=(4V^2)/(R_T)
R_T=2R

Since we are not provided with any voltage or resistance, we simply have to leave the answer as R_T=2R, where R is the resistance of 1 resistor.