Question #64b3c

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Answer 1 · 2014-10-14T22:45:38

Let us first find the function values at #t=1# and #t=2#.

#s(2)=-16(2)^2+16(2)+32=0#

#s(1)=-16(1)^2+16(1)+32=32#

The average rate of change of #s# on #[1,2]# can be found by

#{s(2)-s(1)}/{2-1}={0-32}/{1}=-32#

This means that the value of #s# decreases by #32# units on the average as #t# increases #1# unit.

I hope that this was helpful.