How do you multiply and simplify to the lowest terms #\frac{x^3}{2y^3} \cdot \frac{2y^2}{x}#?

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Answer 1 · 2014-11-03T04:37:22

#{x^3}/{2y^3}cdot{2y^2}/{x}#

by multiplying the numerators together and the numerators together,

#={x^3cdot2y^2}/{2y^3 cdot x}={2x^3y^2}/{2xy^3}#

by dividing the numerator and the denominator by #2#,

#={x^3y^2}/{xy^3}#

by dividing the numerator and the denominator by #x#,

#={x^2y^2}/{y^3}#

by dividing the numerator and the denominator by #y^2#,

#={x^2}/{y}#

I hope that this was helpful.