Question

Question #0d44a

Answer 1

When an electron jumps from a higher energy orbit to lower energy orbit, light is emitted. The enregy of the light emitted is equal to the energy difference between the two orbits.

Here, the energy difference is `3*10^(-19)J`.

Energy of light is given by `(h*c)/lambda`

So, #3*10^(-19)=(h*c)/lambda rArr 3*10^(-19)=(6.626*10^(-34)*3*10^8)/lambda rArr lambda=(6.626*3*10^(-34+8+19))/3rArr lambda=6.626*10^(-7)m#