How do you Find the Riemann sum for $f(x)=x^3$ on the interval $[0,5]$ using right endpoints with $n=8$ ?

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Answer 1 · 2014-11-12T15:24:41

Let us find $Delta x$ .

$Delta x={b-a}/n={5-0}/8=5/8$

Now, we can find the right sum $R_8$ .

$R_8=[f(5/8)+f(10/8)+f(15/8)+f(20/8)+f(25/8)+f(30/8)+f(35/8)+f(40/8)]cdot Delta x$

$=[(5/8)^3+(10/8)^3+(15/8)^3+(20/8)^3+(25/8)^3+(30/8)^3+(35/8)^3+(40/8)^3]cdot 5/8$

$approx 197.75$

How do you Find the Riemann sum for f(x)=x^3f(x)=x^3 on the interval [0,5][0,5] using right endpoints with n=8n=8?