What is the rate of reaction if #"12.0 mL H"_2"# gas is produced in #"30.0 s"# at STP?

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Answer 1 · 2014-11-25T08:53:09

The reaction rate is #"0.0000176 mol H"_2"/s"#.

At STP, one mole of a gas occupies #"22.4"# liters.

#"12.0 mL"# = #"0.0120L"#.

At STP of #"0"^@"C"# and #10^5# #"Pa"#, the molar volume of a gas is #"22.711 L/mol"#.

To calculate the number of moles of #"H"_2# gas produced, multiply the volume of gas produced in liters times #"1 mol H"_2/"22.711 L H"_2"#.

#"0.0120L H"_2xx("1 mol H"_2)/("22.711 L H"_2)= "0.000528 mol H"_2"#

To calculate the rate of reaction in mol/s, divide the number of moles by #"30.0s"#.

#"reaction rate"## = ##"0.000528 mol H"_2/"30.0s" = "0.0000176 mol H"_2"/s"#