Question

Question #c73aa

Answer 1

Since the denominator cannot be zero,

`x^2-x-12=(x+3)(x-4) ne 0 => x ne -3, 4`

So, the domain of `f` is

`D_{f}=(-infty,-3)cup(-3,4)cup(4,infty)`

To find the range, you need to know what its graph looks like.

Since the graph extends from `-infty` to `infty`, the range of `f` is

`R_{f}=(-infty, infty)`

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I hope that this was helpful.