Question #a6782

1 Answer
Nov 26, 2014

#8xy-12y+2x-3=0#

by factoring #4y# out of the first two terms,

#=>4y(2x-3)+(2x-3)=0#

by factoring out #(2x-3)#,

#=>(2x-3)(4y+1)=0#

since it has to be true for all values of #y#,

#=>2x-3=0 => x=3/2#

Hence, the correct answer is (D).


I hope that this was helpful.