Question #83975

1 Answer
Dec 5, 2014

Geometric Series

#a+ar+ar^2+ cdots = a/{1-r}" "# if #" "-1 < r < 1#


Since

#b(1+b+b^2+ cdots)=b+b^2+b^3+ cdots#

is a geometric series with #{(a=b),(r=b):}#, its sum #S# can be found by

#S=b/{1-b}" "# if #" "-1 < b < 1#.

For other values of #b#, the series diverges.


I hope that this was helpful.