What is the integral of #ln(7x)#?

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Answer 1 · 2014-12-09T01:01:21

#int u dv=uv- int v du#

Let #u=ln(7x)" "# #" "dv=dx#
#=> du={dx}/x" "# #" "=> v=x#

By Integration by Parts,

#int ln(7x) dx=ln(7x) cdot x- int x cdot {dx}/x#

#=x ln(7x)-int dx+C#

#=x ln(7x) - x+C#

I hope that this was helpful.