How can I compute the intensity of a polarized wave going through a Polaroid?

1 Answer
Dec 21, 2014

You could use Malus' Law.
Malus' Law tells us that if you have a polarized wave (of intensity I0) passing through a polarizer the emerging intensity ( I ) will be proportional to the cosine squared of the angle between the polarizing direction of the incoming wave and the axis of the polarizer.

Or: I=I0cos2(θ)

Sounds difficult but look at the picture:
enter image source here

Knowing the angle θ and the incoming intensity you´ll be able to evaluate the output intensity.

Special case :
When you have unpolarized light falling upon the polarizer the transmitted intensity will be 12 of the incoming intensity, i.e.:
I=I02
(to understand this, look at the mathematical explanation that follows and remember that the average value of cos2 is 12!!!)

As a mathematical explanation you have:
If E0 is the amplitude of the electric vector of the incoming wave, then the intensity I0 of the wave incident on the polarizer is proportional to E02.

The electric field vector E0 of the incoming wave can be resolved into two rectangular components projected upon the polarizer axis:
E0cos(θ) and E0sin(θ)
The analyzer will transmit only the component ( i.e E0cos(θ)) which is parallel to its transmission axis.
enter image source here
But intensity is proportional to the square of the electric vector you have:
IE2 and:
I(E0cos(θ))2 but:
II0=(E0cos(θ))2E02

and finally:
I=I0cos2(θ)