How do I find the focus of the parabola with the equation #y=1/4x^2-3/2x+1/4#?
1 Answer
You are in the simplest case of this kind of exercises, since you already have the parabola written in the form
The general rule says that, in this case, the coordinates of the focus are
where
Let's compute this out for your values: you have
So,
and
Thus,
The focus of your parabola has thus coordinates
This is the graph of your parabola, you'll see that the result we got is quite reasonable
graph{x^2/4-3x/2+1/4 [-10, 10, -5, 5]}