Question

Question #cc999

Answer 1

The answer is:

`y'=(1/(2sqrt(2x-1))*2*lnx-sqrt(2x-1)*1/x)/(ln^2x)=((xlnx-(2x-1))/(xsqrt(2x-1)))/(ln^2x)=(xlnx-2x+1)/(xsqrt(2x-1)ln^2x`

The rule that has been applied is the derivative of a quotient, that is:

`y=f(x)/g(x)rArry'=(f'(x)g(x)-f(x)g'(x))/(g^2(x)`