How do you factor #x^2-26x^3-27#?

1 Answer
Feb 4, 2015

Factoring a polynomial (when possible using real numbers) means to find its roots, and then divide the polynomial for the linear factor #(x-x_i)#, where #x_i# is the root.

In your case, you can see that #x=-1# is a root, since
#(-1)^2 -26(-1)^3-27=1+26-27=0#.

Dividing your polynomial by #(x+1)#, you obtain #-(26x^2-27x+27)#. The discriminant of this quadratic polynomial is #-2079#, and thus it has no real solutions. We cannot further simplify it, and so the answer is
#-(x+1)(26x^2-27x+27)#