Question

How do you solve `x-5y=15` and `4x-3y=26` using substitution?

Answer 1

you can isolate `x` from the first equation giving:
`x=5y+15` and substitute in the second:
`4(5y+15)-3y=26`
`20y+60-3y=26`
`17y=-34`
`y=-2`

Substituting back in: `x=5y+15` it gives you:
`x=-10+15=5`