Question

How do you find the derivative of the function `f(x)=9x^2ln(8x)`?

Answer 1

The answer is: `y'=9x(2ln8x+1)`.

For the rule of product and for the chain rule:

`y'=9(2x*ln8x+x^2*1/(8x)*8)=9(2x*ln8x+x)=`

`=9x(2ln8x+1)`.