Question

Question #a7d58

Answer 1

The theoretical yield of ethyl butyrate is 10.3 g. The percent yield was 54.9 %.

Explanation:

The balanced equation is

`"CH"_3"CH"_2"CH"_2"COOH" + "HOCH"_2"CH"_3 → "CH"_3"CH"_2"CH"_2"COOCH"_2"CH"_3 +"H"_2"O"`

For easier typing, let's re-write this equation as

`"PrCOOH" + "HOEt" → "PrCOOEt" + "H"_2"O"`

Theoretical yield

`7.80 color(red)(cancel(color(black)("g PrCOOH"))) × (1 color(red)(cancel(color(black)("mol PrCOOH"))))/(88.11 color(red)(cancel(color(black)("g PrCOOH")))) × (1 color(red)(cancel(color(black)("mol PrCOOEt"))))/(1 color(red)(cancel(color(black)("mol PrCOOH")))) × (116.2color(white)(l) "g PrCOOEt")/(1 color(red)(cancel(color(black)("mol PrCOOEt"))))`

`=color(white)(l) "10.3 g PrCOOEt"`

Percentage Yield

`"% Yield" = "Actual yield"/"Theoretical yield" × 100 % = (5.65 color(red)(cancel(color(black)("g"))))/(10.3 color(red)(cancel(color(black)("g")))) × 100 % = 54.9 %`