Question

Question #c2359

Answer 1

Find the angles first (`3x`), then find `x`.

The cosine of some angle is to be `sqrt3/2`.

The angles with that cosine are all of the form: `pi/6+2pik` or `-pi/6+2pik` for integer `k`.

This tells us that `3x` must be `pi/6+2pik` or `-pi/6+2pik` for integer `k`.

Solve the two equations

`3x=pi/6+2pik` and `3x=-pi/6+2pik` for `x`.