What is the molarity if #"11 g CaCl"_2"# are dissolved in one liter of solution?

1 Answer
Ernest Z. · Meave60
Mar 16, 2015

The molarity of CaCl₂ is 0.99 mol/L.

To get the molarity, you divide the moles of solute by the litres of solution.

#"Molarity" = "moles of solute"/"litres of solution"#

#"Moles of CaCl₂" = 11 cancel("g CaCl₂") ×"1 mol CaCl₂"/(110.98 cancel("g CaCl₂")) = "0.099 mol CaCl₂"#.

#"Litres" = "100 mL" = "0.100 L"#

#"Molarity" = "moles of solute"/"litres of solution" = "0.099 mol"/"0.100 L" = "0.99 mol/L"#

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