What is the final temperature of water if it used 520 J from 52 degrees C?

1 Answer

The final temperature depends on the mass of the water, and the mass must be sufficient that the water does not boil.

But we can do a general calculation.

q = mcΔTq=mcΔT

ΔT = T_2 –T_1 = q/(mc)ΔT=T2T1=qmc

T_2 = T_1 + q/(mc)T2=T1+qmc

Using your values, we get

T_2 = "52 °C" + (520 cancel("J"))/(m × 4.184 cancel("J")"g⁻¹°C⁻"¹)T2=52 °C+520Jm×4.184Jg¹°C¹

T_2 = "52 °C" + "124 g°C"/mT2=52 °C+124 g°Cm

Now you can insert your own value of mm and calculate the value of T_2T2.